question_answer

An alternating voltage \[\text{v}(t)=220\sin 100\pi t\] volt is applied to a purely resistance load of \[50\Omega .\]. The time taken for the current to rise from half of the peak value to the peak value is : [JEE Main 8-4-2019 Morning]

A) 2.2 ms

B) 5 ms

C) 3.3 ms

D) 7.2 ms

Correct Answer: C

Solution :

[c]

time taken,