JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा JEE PYQ-Alternating Current

  • question_answer
    In an oscillating LC circuit, the maximum charge on the capacitor is 0. The charge on the capacitor when the energy is stored equally between the electric and magnetic fields is [AIEEE 2003]

    A) \[Q/2\]

    B) \[Q/\sqrt{3}\]

    C) \[Q/\sqrt{2}\]

    D) Q

    Correct Answer: C

    Solution :

    [c] In an LC circuit, the energy oscillates between inductor (in the magnetic field) and capacitor (in the electric field).
    Maximum energy stored in capacitor
                                        \[{{U}_{E\max }}=\frac{{{Q}^{2}}}{2C}\]
    Maximum energy stored in inductor
                            \[{{U}_{B\max }}=\frac{Ll_{0}^{2}}{2}\]
    where, \[{{l}_{0}}\] is the current at this time.
    For the given instant \[{{U}_{E}}={{U}_{B}}\]
    \[i.e.,\]   \[\frac{{{q}^{2}}}{2C}=\frac{L{{i}^{2}}}{2}\]
    From energy conservation
                            \[{{U}_{E}}+{{U}_{8}}={{U}_{E\max }}={{U}_{B\max }}\]
    \[\Rightarrow \]   \[2\frac{{{q}^{2}}}{2C}=\frac{{{Q}^{2}}}{2C}\]
    \[\Rightarrow \]   \[q=\frac{Q}{\sqrt{2}}\]


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