A) \[\frac{10}{\sqrt{74}}\]
B) \[\frac{20}{\sqrt{74}}\]
C) \[\frac{10}{\sqrt{83}}\]
D) \[\frac{5}{\sqrt{83}}\]
Correct Answer: C
Solution :
Normal vector \[\left| \begin{matrix} {\hat{i}} & {\hat{j}} & {\hat{k}} \\ 1 & -2 & 3 \\ 2 & -1 & -1 \\ \end{matrix} \right|=5\hat{i}+7\hat{j}+3\hat{k}\] So plane is \[5(x-1)+7(y+1)+3(z+1)=0\] \[\Rightarrow \]\[5x+7y+3z+5=0\] Distance \[\frac{5+21-21+5}{\sqrt{25+49+9}}=\frac{10}{\sqrt{83}}\]You need to login to perform this action.
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