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JEE Main & Advanced JEE Main Solved Paper-2016

  • question_answer
    The equilibrium constants at 298 K for a reaction \[A+BC+D\]is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol\[{{L}^{-1}}\]) will be : [JEE Main Solved Paper-2016 ]

    A) 1.182                    

    B)  0.182

    C) 0.818                    

    D) 1.818

    Correct Answer: D

    Solution :

                    \[A+BC+D\]        \[K=100\]                 \[Q=\frac{1\times 1}{1\times 1}=1\] \[\because \]\[Q<K\] so reaction moves in foward reaction
      \[A+B\] \[\] \[C+D\]
    Initial 1       1   10     10
    At equ. 1-x   1-x   1+x   1+x
    \[\frac{{{(1+x)}^{2}}}{{{(1-x)}^{2}}}=100\Rightarrow \frac{1+x}{1-x}=10\] \[1+x=10-10x\Rightarrow x=\frac{9}{11}\] \[\therefore \]\[[D]=1+x=1+\frac{9}{11}=1.818M\]


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