A) \[{{H}_{3}}P{{O}_{4}}\]
B) \[{{H}_{2}}S{{O}_{3}}\]
C) \[{{H}_{2}}{{O}_{2}}\]
D) \[HN{{O}_{2}}\]
Correct Answer: A
Solution :
[a] In\[{{H}_{3}}P{{O}_{4}}\], P is present in +5 oxidation state and it can act as reducing agent only
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