A) Tetraaquadichlorido chromium(III) chloride dehydrate
B) Hexaaqua chromium (III) chloride
C) Tetraaquadichlorido chromium (IV) Chloride dehydrate
D) Dichloridotetraaqua chromium (IV) chloride dehydrate
Correct Answer: A
Solution :
[a] Complex : \[Cr{{\left( {{H}_{2}}O \right)}_{6}}C{{l}_{n}}\] Spin only magnetic moment = \[\sqrt{n\left( n+2 \right)}\]BM \[=\sqrt{3.8}\]BM n = no. of unpaired electrons \[\therefore n=3\] \[\therefore \] Cr is in +3 oxidation state \[\because \] Complex shows geometrical isomerism and also reacts with \[AgN{{O}_{3}}\] \[\therefore \] Complex \[\left[ Cr{{\left( {{H}_{2}}O \right)}_{4}}C{{l}_{2}} \right]Cl.2{{H}_{2}}O\] IUPAC Name : Tetraaquadichloridochromium (III) chloride dihydrateYou need to login to perform this action.
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