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JEE Main & Advanced JEE Main Paper Phase-I (Held on 09-1-2020 Evening)

  • question_answer
    In the figure shown below reactant A (represented by square) is in equilibrium with product B (represented by circle). The equilibrium constant is [JEE MAIN Held on 09-01-2020 Evening]

    A) 4

    B) 2

    C) 8

    D) 1

    Correct Answer: B

    Solution :

    Equilibrium constant \[{{K}_{C}}=\frac{[\text{Product}]}{[\text{Reactant}]}\]                                                 \[\approx 2\]


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