A) \[\frac{\sqrt{3}q}{\pi {{\varepsilon }_{0}}{{d}^{2}}}\]
B) \[\frac{3\sqrt{3}q}{4\pi {{\varepsilon }_{0}}{{d}^{2}}}\]
C) \[\frac{\sqrt{3}q}{4\pi {{\varepsilon }_{0}}{{d}^{2}}}\]
D) \[\frac{2\sqrt{3}q}{\pi {{\varepsilon }_{0}}{{d}^{2}}}\]
Correct Answer: A
Solution :
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