JEE Main & Advanced JEE Main Paper Phase-I (Held on 08-1-2020 Evening)

  • question_answer
    Hydrogen has three isotopes (A), (B) and (C). If the number of neutron(s) in (A), (B) and (C) respectively, are (x), (y) and (z), the sum of (x), (y) and (z) is [JEE MAIN Held on 08-01-2020 Evening]

    A) 4

    B) 2

    C) 3

    D) 1

    Correct Answer: C

    Solution :

    Isotopes of hydrogen and the number of neutrons present in them are Total number of neutrons in three isotopes of hydrogen = 0 + 1 + 2 = 3


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