JEE Main & Advanced JEE Main Paper Phase-I (Held on 08-1-2020 Evening)

  • question_answer
    The radius of the second Bohr orbit, in terms of the Bohr radius, \[{{a}_{0}}\], in \[L{{i}^{2+}}\] is [JEE MAIN Held on 08-01-2020 Evening]

    A) \[\frac{4{{a}_{0}}}{3}\]           

    B) \[\frac{4{{a}_{0}}}{9}\]

    C) \[\frac{2{{a}_{0}}}{3}\]                       

    D) \[\frac{2{{a}_{0}}}{9}\]

    Correct Answer: A

    Solution :

    \[r=0.529\frac{{{n}^{2}}}{z}\overset{\text{o}}{\mathop{\text{A}}}\,\] Bohr?s radius for hydrogen atom \[\left( {{a}_{0}} \right)=0.529\,\overset{\text{o}}{\mathop{\text{A}}}\,\] Bohr?s radius of \[L{{i}^{+2}}\]ion for \[n=2\] \[=\,\,{{a}_{0}}\frac{{{n}^{2}}}{z}\] \[=\,\,\frac{4{{a}_{0}}}{3}\]


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