question_answer

Consider the following reactions:                                                   [JEE MAIN Held on 07-01-2020 Morning]

(A) \[{{(C{{H}_{3}})}_{3}}CCH(OH)C{{H}_{3}}\xrightarrow{conc.{{H}_{2}}S{{O}_{4}}}\]

(B) \[{{(C{{H}_{3}})}_{2}}CHCH(Br)C{{H}_{3}}\xrightarrow{alc.KOH}\]

(C) \[{{(C{{H}_{3}})}_{2}}CHCH(Br)C{{H}_{3}}\xrightarrow{{{(C{{H}_{3}})}_{3}}{{O}^{\Theta }}{{K}^{\oplus }}}\]

(D) \[{{(C{{H}_{3}})}_{2}}\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,-C{{H}_{2}}-CHO\xrightarrow{\Delta }\]

Which of these reaction(s) will not produce Saytzeff product?

A) (A), (C) and (D)

B) (C) only

C) (B) and (D)

D) (D) only

Correct Answer: B

Solution :

[b] Tertiary butoxide is a bulky base and it extracts the least hindered hydrogen