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JEE Main & Advanced JEE Main Paper (Held On 9 April 2017)

  • question_answer
    Adsorption of a gas on a surface follows Freundlich adsorption isotherm. Plot of \[\frac{x}{m}\] versus log p gives a straight line with slope equal to 0.5, then : (\[\frac{x}{m}\] is the mass of the gas adsorbed per gram of adsorbent) [JEE Online 09-04-2017]

    A)  Adsorption is proportional to the square root of pressure.

    B)  Adsorption is proportional to the square of pressure.

    C)  Adsorption is proportional to the pressure.

    D)  Adsorption is independent of pressure.

    Correct Answer: A

    Solution :

                      \[\log \left( \frac{x}{m} \right)\,=\frac{1}{2}\log \,(P)+K\]                 \[\frac{x}{m}+K{{P}^{1/2}}\]


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