A) \[{{10}^{22}}\]
B) \[{{10}^{19}}\]
C) \[{{10}^{20}}\]
D) \[{{10}^{18}}\]
Correct Answer: C
Solution :
\[P=\frac{nhc}{\lambda t}\] \[n=\frac{p\lambda t}{hc}\] \[=5\times {{10}^{3}}\times \,\frac{660\,\times {{10}^{-9}}\times 60\,\times {{10}^{-3}}}{6.6\,\times {{10}^{-34}}\times 3\times {{10}^{8}}}\] \[=100\,\times {{10}^{18}}\,={{10}^{20}}\]
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