JEE Main & Advanced JEE Main Paper (Held On 9 April 2017)

  • question_answer
    The function f defined by \[f(x)={{x}^{3}}-3{{x}^{2}}+5x+7,\] is: [JEE Online 09-04-2017]

    A)  decreasing in R

    B)  increasing in R

    C)  increasing in \[(0,\,\,\infty )\] and decreasing in \[(-\infty ,\,\,0)\]

    D)  decreasing in \[(0,\,\,\infty )\] and increasing in \[(-\infty ,\,\,0)\]

    Correct Answer: B

    Solution :

      \[f(x)={{x}^{3}}-3{{x}^{2}}+5x+7\] \[f'(x)=3{{x}^{2}}-6x+5>0\] \[f'(x)\,=3{{x}^{2}}-6x+5<0\] \[x\in \phi \]


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