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JEE Main & Advanced JEE Main Paper (Held On 9 April 2016)

  • question_answer
    If the mean deviation of the numbers 1, 1 + d, ..., 1 + 100d from their mean is 255, then a value of d is :   JEE Main Online Paper (Held On 09 April 2016)

    A) 10                                          

    B) 20.2

    C) 5.05                                       

    D) 10.1

    Correct Answer: D

    Solution :

                    Mean is\[\frac{101+\frac{100\times 101}{2}}{101}=1+50d\]sum of deviation about mean is 50 d + 49d + ................... d + 0 + d + ........ + 50 d = 50. 51 d Mean deviation \[=\frac{50\times 51d}{101}=255\] \[d=\frac{255\times 101}{2550}=10.1\]


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