A) Mustard oil test
B) \[{{C}_{6}}{{H}_{5}}S{{O}_{2}}Cl\]
C) Sandmeyer's reaction
D) Carbylamine reaction
Correct Answer: B
Solution :
Benzene sulphonyl chloride \[({{C}_{6}}{{H}_{5}}S{{O}_{2}}Cl)\]is used to distinguish primary, secondary and tertiary amine.
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