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JEE Main & Advanced JEE Main Paper (Held On 9 April 2016)

  • question_answer
    200 g water is heated from \[40{}^\circ C\] to \[60{}^\circ C\]. Ignoring the slight expansion of water, the change in its internal energy is closed to (Given specific heat of water = 4184 J/kg/K) :   JEE Main Online Paper (Held On 09 April 2016)

    A) 16.7 kJ  

    B) 167.4kJ

    C) 4.2 kJ                    

    D) 8.4 kJ

    Correct Answer: A

    Solution :

    \[\Delta U=mS\Delta T\]                 \[=\left( \frac{2}{10} \right)(4184)(20)=16736J\] \[=16.7kJ\]                


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