A) Young's modulus < shear modulus < bulk modulus.
B) Bulk modulus < shear modulus < Young's modulus
C) Shear modulus < Young's modulus < bulk modulus.
D) Bulk modulus < Young's modulus < shear modulus.
Correct Answer: C
Solution :
Poisson's ratio,\[\text{ }\!\!\sigma\!\!\text{ }\,\text{=}\frac{\text{lateral}\,\text{strain( }\!\!\beta\!\!\text{ )}}{\text{longitudinal}\,\text{strain( }\!\!\alpha\!\!\text{ )}}\] For material like copper, \[\text{ }\!\!\sigma\!\!\text{ }\,\text{=0}\text{.33}\] And, \[y=3k(1-2\sigma )\] Also,\[\frac{9}{y}=\frac{1}{k}+\frac{3}{n}\] \[y=2n(1+\sigma )\] Hence, n < y < k
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