A) 20 N
B) 10 N
C) 60 N
D) 40 N
Correct Answer: C
Solution :
Mass of bigger body M = 4 kg Mass of smaller body m = 1 kg Smaller mass (m = 1 kg) executes S.H.M of angular frequency \[\omega =25\]rad/s Amplitude \[x=1.6cm=1.6\times {{10}^{-2}}\] As we know,\[T=2\pi \sqrt{\frac{m}{K}}\]or\[\frac{2\pi }{\omega }=2\pi \sqrt{\frac{m}{K}}\] or\[\frac{1}{25}=\sqrt{\frac{1}{K}}[\because m=1kg;\omega =25rad/s]\] or\[K=625N{{m}^{-1}}.\] The maximum force exerted by the system on the floor \[=Mg+Kx+mg\] \[=4\times 10+625\times 1.6\times {{10}^{-2}}+1\times 10\] \[=40+10+10\]You need to login to perform this action.
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