A) 1.7%
B) 2.7%
C) 4.4%
D) 2.27%
Correct Answer: B
Solution :
According to the question. \[T=(90\pm 1)\]or,\[\frac{\Delta t}{t}=\frac{1}{90}\] \[l=(20\pm 0.1)\]or\[\frac{\Delta l}{l}=\frac{0.1}{20}\] \[\frac{\Delta g}{g}%=?\] As we know,\[t=2\pi \sqrt{\frac{l}{g}}\]\[\Rightarrow \]\[g=\frac{4{{\pi }^{2}}l}{{{t}^{2}}}\] or\[\frac{\Delta g}{g}=\pm \left( \frac{\Delta l}{l}+2\frac{\Delta t}{t} \right)\] \[=\left( \frac{0.1}{20}+2\times \frac{1}{90} \right)\] \[=0.027\] \[\therefore \]\[\frac{\Delta g}{g}%=2.7%\]You need to login to perform this action.
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