JEE Main & Advanced JEE Main Paper (Held on 7 May 2012)

  • question_answer
    The heat radiated per unit area in 1 hour by a furnace whose temperature is 3000 K is \[(\sigma =5.7\times {{10}^{-8}}W\,{{m}^{-2}}{{K}^{-4}})\]   JEE Main Online Paper (Held On 07 May 2012)

    A) \[1.7\times {{10}^{10}}J\]            

    B)                        \[1.1\times {{10}^{12}}J\]

    C)                        \[2.8\times {{10}^{8}}J\]                              

    D)                        \[4.6\times {{10}^{6}}J\]

    Correct Answer: A

    Solution :

                    According to Stefan9 slaw\[E=\sigma {{T}^{4}}\] Heat radiated per unit area in 1 hour (3600s) is\[=5.7\times {{10}^{-8}}\times {{(300)}^{4}}3600=1.7\times {{10}^{10}}J\]                


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