JEE Main & Advanced JEE Main Paper (Held on 7 May 2012)

  • question_answer
    A car of mass 1000 kg is moving at a speed of 30m/s. Brakes are applied to bring the car to rest. If the net retarding force is 5000 N, the car comes to stop after travelling dm in t s. Then JEE Main Online Paper (Held On 07 May 2012)

    A) \[d=150,t=5\]                   

    B)                        \[d=120,t=8\]

    C)                        \[d=180,t=6\]                   

    D)                        \[d=90,t=6\]

    Correct Answer: D

    Solution :

                    Given: mass of car m = 1000 kg u =30m/s v = 0 m/s retarding force f = 5000 N \[\therefore \]retardation, \[-a=\frac{5000}{1000}=5\,m/{{s}^{2}}\] By equation, \[{{v}^{2}}-{{u}^{2}}=2as\] \[0-{{(30)}^{2}}=-2\times 5\times d\] \[\therefore \]\[d-\frac{900}{10}=90m\] and\[a=\frac{v-u}{t}\therefore t=\frac{v-u}{a}=\frac{0-30}{-5}=6s\]


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