JEE Main Online Paper (Held On 07 May 2012)
A) \[{{v}_{A}}={{v}_{B}}=0.5m/s\]
B) \[{{v}_{A}}=0.5m/s<{{v}_{B}}\]
C) \[{{v}_{A}}=0.5m/s>{{v}_{B}}\]
D) \[{{v}_{A}}={{v}_{B}}=2m/s\]
Correct Answer: A
Solution :
Instantaneous velocity \[v=\frac{\Delta x}{\Delta t}\] Fromgraph.\[{{v}_{A}}=\frac{\Delta {{x}_{A}}}{\Delta {{t}_{A}}}=\frac{4m}{8s}=0.5m/s\] and\[{{v}_{B}}=\frac{\Delta {{x}_{B}}}{\Delta {{t}_{B}}}=\frac{8m}{16s}=0.5m/s\] i.e.,\[{{v}_{B}}={{v}_{B}}=0.5m/s\]
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