A) \[m{{v}^{3}}\]
B) \[m{{v}^{2}}\]
C) \[\frac{1}{2}m{{v}^{2}}\]
D) \[\frac{1}{2}m{{v}^{3}}\]
Correct Answer: B
Solution :
As power\[P=F.v.=\frac{F.\ell }{t}\]or,\[v\left( M\frac{v}{t} \right)=\frac{F.\ell }{t}\] \[\Rightarrow \]\[M{{v}^{2}}=F.\ell \]\[\Rightarrow \]\[F={{\frac{M}{\ell }}^{2}}{{v}^{2}}=m{{v}^{2}}\] \[\left[ \because \frac{M}{\ell }\text{=}\left( \text{given} \right) \right]\]
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