A) \[F>O>N>C\]
B) \[O>N>F>C\]
C) \[C>N>O>F\]
D) \[O>F>N>C\]
Correct Answer: D
Solution :
In a period the value of ionisation potential increases from left to right with breaks where the atoms have some what stable configuration. After removing an \[{{e}^{-}}\]oxygen will acquire stable configuration. Hence \[{{O}^{+}}\]has highest second ionization enthalpy than \[{{F}^{+}}\] and \[{{N}^{+}}.\] \[\therefore \]correct order is O> F > N > C
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