JEE Main & Advanced JEE Main Paper (Held On 26 May 2012)

  • question_answer
    Consider the following sequence of reactions \[C{{H}_{3}}CH=C{{H}_{2}}\xrightarrow[700K]{C{{l}_{2}}}A\xrightarrow[420K,12atm]{N{{a}_{2}}C{{O}_{3}}}\]\[B\xrightarrow[(ii)NaOH]{(i)HOCl}C\] Compound 'C' is.   JEE Main Online Paper (Held On 26-May-2012)  

    A) \[\underset{\begin{align}   & | \\  & CHOH \\  & | \\  & C{{H}_{2}}OH \\ \end{align}}{\mathop{C{{H}_{2}}OH}}\,\]            

    B) \[C{{H}_{3}}\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{CH}}\,COONa\]

    C) \[HOC{{H}_{2}}-CH=C{{H}_{2}}\]

    D) \[C{{H}_{3}}\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{CH}}\,COCl\]

    Correct Answer: A

    Solution :

                   


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