JEE Main & Advanced JEE Main Paper (Held On 26 May 2012)

The figure shows a combination of two NOT gates and a NOR gate. The combination is equivalent to a. JEE Main Online Paper (Held On 26-May-2012)

A) NAND gate

B)                        NOR gate

C)                        AND gate

D)                        OR gate

Correct Answer: C

Solution :

Truth table is as shown :

A	B	\[\overline{\text{A}}\]	\[\overline{\text{B}}\]	\[\overline{\text{A}}+\overline{\text{B}}\]	\[\overline{\overline{\text{A}}+\overline{\text{B}}}\]
0	0	1	1	1	0
0	1	1	0	1	0
1	0	0	1	1	0
1	1	0	0	0	1

Thus the combination of two NOT gates and one NOR gate is equivalent to a AND gate.