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JEE Main & Advanced JEE Main Paper (Held On 25 April 2013)

  • question_answer
                    In the isothermal expansion of 10g of gas from volume V to 2V the work done by the gas is 575J. What is the root mean square speed of the molecules of the gas at that temperature?     JEE Main Online Paper ( Held On 25  April 2013 )

    A)                 398 m/s                               

    B)                                        520m/s

    C)                                        499m/s                

    D)                                        532m/s

    Correct Answer: C

    Solution :

                    \[{{v}_{rms}}=\sqrt{\frac{3\rho v}{mass\,of\,the\,gas}}\]


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