Looking at the graphs, you can most appropriately say that:
JEE Main Online Paper ( Held On 25 April 2013 )
A) Work function of metal B is greater that that of metal A
B) for light of certain wavelength falling on both metal, maximum kinetic energy of those emitted from B.
C) Work function of metal A is greater than that of metal B
D) Students data is not correct
Correct Answer: D
Solution :
\[\frac{hc}{\lambda }-\phi =e{{V}_{0}}\] \[{{v}_{0}}=\frac{hc}{e\lambda }-\frac{\phi }{e}\] For metal A For metal B \[\frac{\phi A}{hc}=\frac{1}{\lambda }\] \[\frac{\phi B}{hc}=\frac{1}{\lambda }\] As the value of \[\frac{1}{\lambda }\](increasing and decreasing) is not specified hence we cannot say that which metal has comparatively greater or lesser work function \[(\phi ).\]
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