A) \[n+4{{n}^{2}}\]
B) \[6{{n}^{2}}-n\]
C) \[{{n}^{2}}+4n\]
D) \[3n+2{{n}^{2}}\]
Correct Answer: B
Solution :
Given \[{{S}_{n}}=2n+3{{n}^{2}}\] Now, first term = 2 + 3 = 5 second term = 2(2) + 3(4) = 16 third term =2(3) +3 (9) =33 Now, sum given in option (b) only has the same first term and difference between 2nd and 1st term is double also.
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