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JEE Main & Advanced JEE Main Paper (Held On 22 April 2013)

  • question_answer
    A body stars from rest on a long inclined plane of slope\[{{45}^{o}}\]. The coefficient of friction between the body and the plane varies as \[\mu =0.3\,x,\] where \[x\] is distance travelled down the down the plane. The body will have maximum speed (for g=10 m/\[{{\text{s}}^{\text{2}}}\]) when \[x\]= :     JEE Main  Online Paper (Held On 22 April 2013)

    A)  9.8 m

    B)  27 m

    C)  12 m                                     

    D)  3.33 ms

    Correct Answer: D

    Solution :

     When the body has maximum speed then \[\mu =0.3x=\tan {{45}^{o}}\] \[\therefore \,\,x=3.33\,\,m\]


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