JEE Main & Advanced JEE Main Paper (Held On 22 April 2013)

  • question_answer
    Which of the following would not give 2-phenylbutane as the major product in a Friedel-Crafts alkylation reaction?     JEE Main  Online Paper (Held On 22 April 2013)

    A)  1-butene + HF

    B)  2-butanol+ \[{{\operatorname{H}}_{2}}{{\operatorname{SO}}_{4}}\]

    C)  Butanoykhloride \[+AlC{{l}_{3}}\] then \[Zn,\,HCl\]

    D)  Butyl chloride \[+AlC{{l}_{3}}\]

    Correct Answer: C

    Solution :

     The Friedal-crafts alkylation reaction will give propyi phenyl ketone which further on Clemmenson 's reduction will give butyl benzene \[{{C}_{6}}{{H}_{6}}+C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}COCl\xrightarrow{AlC{{l}_{3}}}\] \[{{C}_{6}}{{H}_{5}}COC{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\xrightarrow{Zn-Hg/HCl}\] \[\underset{Bultyl\,bezene}{\mathop{{{C}_{6}}{{H}_{5}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,\]               

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