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JEE Main & Advanced JEE Main Paper (Held On 22 April 2013)

  • question_answer
                    Figure shows a circuit in which three identical diodes are used. Each diode has forward resistance of 20 \[\Omega \] and infinite backward resistance. Resistors \[{{\operatorname{R}}_{1}}={{\operatorname{R}}_{2}}={{\operatorname{R}}_{3}}=50\Omega \]. Battery voltage is 6 V. The current though \[{{\operatorname{R}}_{3}}\].     JEE Main  Online Paper (Held On 22 April 2013)

    A)   50 mA                 

    B)  100 mA

    C)   60 mA                 

    D)  25 mA

    Correct Answer: A

    Solution :

     Here, diodes \[{{\text{D}}_{\text{1}}}\]and \[{{\text{D}}_{2}}\]are forv/ard biased and \[{{\text{D}}_{3}}\]is reverse biased. Therefore current through \[{{R}_{3}}\] \[i=\frac{V}{R'}=\frac{6}{120}=\frac{1}{20}A=50\,mA\]


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