JEE Main & Advanced JEE Main Paper (Held On 22 April 2013)

  • question_answer
    To find the resistance of galvanometer by the half deflection method the following circuit is used with resistances \[{{\operatorname{R}}_{1}}=9970\Omega ,{{\operatorname{R}}_{2}}=30\Omega \] and \[{{\operatorname{R}}_{3}}=0\]. The deflection in the galvanometer is d. With \[{{\operatorname{R}}_{3}}=107\Omega \]the deflection changed to \[\frac{\operatorname{d}}{2}.\] The galvanometer resistance is approximately:                    JEE Main  Online Paper (Held On 22 April 2013)

    A)  \[107\Omega \]                  

    B)  \[137\Omega \]

    C)  \[107/2\Omega \]                              

    D)  \[77\,\Omega \]

    Correct Answer: D

    Solution :

     Not Available


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