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JEE Main & Advanced JEE Main Paper (Held On 19 May 2012)

  • question_answer
    Sand is being dropped on a conveyer belt at the rate of 2 kg per second. The force necessary to keep the belt moving with a constant speed of 3 \[\text{m}{{\text{s}}^{\text{-1}}}\]will be     JEE Main  Online Paper (Held On 19  May  2012)

    A) 12N                                       

    B) 6N

    C) zero   

    D) 18N

    Correct Answer: B

    Solution :

    Here, rate of fall of sand on conveyer belt,\[\frac{dm}{dt}=2kg\,{{s}^{-1}}\] Conveyer belt speed \[v=s\,m{{s}^{-1}}\] Force F = ? \[F=v\frac{dm}{dt}=3\times 2=6N\]


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