A) \[2\sqrt{2}T\]
B) 4 T
C) 2 T
D) 8 T
Correct Answer: C
Solution :
\[T{{V}^{\gamma -1}}=\] constant \[{{T}_{1}}{{V}_{1}}^{\gamma -1}={{T}_{2}}{{V}_{2}}^{\gamma -1}\]\[\Rightarrow \]\[T{{(V)}^{{}^{1}/{}_{2}}}={{T}_{2}}{{\left( \frac{V}{4} \right)}^{{}^{1}/{}_{2}}}\] \[\left[ \because \gamma =1.5,{{T}_{1}}=T,{{V}_{1}}=V\,\text{and}\,V=\frac{V}{4} \right]\] \[\therefore \]\[{{T}_{2}}={{\left( \frac{4V}{V} \right)}^{{}^{1}/{}_{2}}}T=2T\]
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