2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced JEE Main Paper (Held On 12-Jan-2019 Evening)

  • question_answer
    In a class of 60 students, 40 opted for NCC, 30 opted for NSS and 20 opted for both NCC and NSS. If one of these students is selected at random, then the probability that the student selected has opted neither for NCC nor for NSS is [JEE Main Online Paper Held On 12-Jan-2019 Evening]

    A) \[\frac{1}{6}\]                                      

    B) \[\frac{5}{6}\]

    C) \[\frac{1}{3}\]                          

    D)   \[\frac{2}{3}\]

    Correct Answer: A

    Solution :

    Let C and S represents the set of students who opted for NCC and NSS respectively. \[\therefore \]\[n(C)=40,n(S)=30,n(C\cup S)=20\] Now,\[n(C\cup S)=40+30-20=50\] So, number of students who has opted neither for NCC nor for NSS are \[60-50=10\] So, P(Neither C nor S)\[\frac{10}{60}=\frac{1}{6}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner