JEE Main & Advanced JEE Main Paper (Held On 12-Jan-2019 Evening)

  • question_answer
    To double the covering range, or' a TV transmission tower, its height should be multiplied by [JEE Main Online Paper Held On 12-Jan-2019 Evening]

    A) \[\frac{1}{\sqrt{2}}\]                             

    B) 2     

    C) 4                                 

    D)   \[\sqrt{2}\]

    Correct Answer: C

    Solution :

    The distance to horizon, of the transmitting tower, \[d=\sqrt{2gh}\] \[\frac{{{d}_{2}}}{{{d}_{1}}}=\sqrt{\frac{{{h}_{2}}}{{{h}_{1}}}}\Rightarrow \frac{2{{d}_{1}}}{{{d}_{1}}}=\sqrt{\frac{{{h}_{2}}}{{{h}_{1}}}}\Rightarrow {{h}_{2}}=4{{h}_{1}}\]


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