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JEE Main & Advanced JEE Main Paper (Held On 12 April 2014)

  • question_answer
    The amount of \[BaS{{O}_{4}}\]formed upon mixing 100 mL of 20.8% \[{{H}_{2}}S{{O}_{4}}\] solution with 50 mL of 9.8% \[{{H}_{2}}S{{O}_{4}}\]solution with 50 mL of 9.8% \[{{H}_{2}}S{{O}_{4}}\] solution will be: (Ba = 137, Cl = 35.5, S = 32, H = 1 and O = 16)   [JEE Main Online Paper ( Held On 12 Apirl  2014 )

    A) 23.3 g                   

    B) 11.65 g

    C) 30.6 g                   

    D) 33.2 g

    Correct Answer: A

    Solution :

                    \[\underset{\begin{smallmatrix}  208g \\    \\  20.8g \end{smallmatrix}}{\mathop{BaC{{l}_{2}}}}\,+\underset{\begin{smallmatrix}  208g \\    \\  20.8g \end{smallmatrix}}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\xrightarrow[{}]{{}}\underset{\begin{smallmatrix}  233g \\    \\  23.3g \end{smallmatrix}}{\mathop{BaS{{O}_{4}}}}\,+\underset{\begin{smallmatrix}  73g \\    \\  7.3g \end{smallmatrix}}{\mathop{2HCl}}\,\]


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