A) \[{{H}_{2}}\]
B) \[C{{l}_{2}}\]
C) \[{{O}_{2}}\]
D) \[{{F}_{2}}\]
Correct Answer: A
Solution :
\[\because \]\[C=\sqrt{\frac{3RT}{M}}\] \[{{(1930)}^{2}}=\frac{3\times 8.314\times 300}{M}\] \[M=\frac{3\times 8.314\times 300}{1930\times 1930}\approx 2\times {{10}^{-3}}kg\] The gas is \[{{H}_{2}}.\]
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