JEE Main & Advanced JEE Main Paper (Held On 12 April 2014)

  • question_answer
    A Carnot engine absorbs 1000 J of heat energy from a reservoir at \[127{}^\circ C\] and rejects 600 J of heat energy during each cycle. The efficiency of engine and temperature of sink will be:   [JEE Main Online Paper ( Held On 12 Apirl  2014 )

    A) \[20%\text{ }and\,\,-43{}^\circ C\]

    B) \[40%\text{ }and\,\,-33{}^\circ C\]

    C) \[50%\text{ }and\,\,-20{}^\circ C\]

    D) \[70%\text{ }and\,\,-10{}^\circ C\]    

    Correct Answer: B

    Solution :

      Given :                 \[{{Q}_{1}}=1000J\] \[{{Q}_{2}}=600J\]                                                 \[{{T}_{1}}={{127}^{o}}C=400K\]                                                 \[{{T}_{2}}=?\]                                                 \[\eta =?\] Efficiency of carnot engine, \[\eta =\frac{W}{{{Q}_{1}}}\times 100%\]or\[\eta =\frac{{{Q}_{2}}-{{Q}_{1}}}{{{Q}_{1}}}\times 100%\] or, \[\eta =\frac{1000-600}{1000}\times 100%\]\[\eta =40%\] \[\frac{600}{1000}=\frac{{{T}_{2}}}{400}\]                             \[{{T}_{2}}=\frac{600\times 400}{1000}\] \[=240K\]                            \[=240-273\] \[{{T}_{2}}=-{{33}^{o}}C\]


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