A) \[\frac{1}{2}\frac{{{e}^{2}}}{r}\]
B) \[-\frac{{{e}^{2}}}{r}\]
C) \[m{{e}^{2}}\]
D) \[1\,{{e}^{2}}\]
Correct Answer: D
Solution :
Total energy of a revolving electron is the sum of its kinetic and potential energy. Total energy = K.E. + P. E. \[=\frac{{{e}^{2}}}{2r}+\left( -\frac{{{e}^{2}}}{r} \right)\] \[=-\frac{{{e}^{2}}}{2r}\]
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