A) 10 N
B) 7.5 N
C) 5 N
D) 12.5 N
Correct Answer: D
Solution :
The given wave is \[y=0.03\text{ }sin\text{ }(450t\text{ }-9x)\] Compare with standard wave equation \[y=a\sin (\omega t-kx)\] The velocity of travelling wave \[v=\frac{\omega }{k}\] \[\Rightarrow \]\[v=\frac{450}{9}=50m/s\] ...(i) Also, velocity of wave on stretched string is \[v=\sqrt{\frac{T}{\mu }}\] ...(ii) Using (i) and (ii), \[\sqrt{\frac{T}{\mu }}=50\Rightarrow T={{(50)}^{2}}\times 5\times {{10}^{-3}}\]\[\Rightarrow \]\[T=12.5N\]
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