JEE Main & Advanced JEE Main Paper (Held On 11-Jan-2019 Evening)

  • question_answer
    A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of \[20\times {{10}^{-6}}J/T\] when a magnetic intensity of \[60\times {{10}^{3}}A/m\]is applied. Its magnetic susceptibility is [JEE  Main Online Paper (Held on 11-jan-2019 Evening)]

    A) \[3.3\times {{10}^{-2}}\]                                 

    B) \[4.3\times {{10}^{-2}}\]

    C) \[3.3\times {{10}^{-4}}\]                     

    D)   \[2.3\times {{10}^{-2}}\]

    Correct Answer: C

    Solution :

    Intensity of magnetization \[I=\frac{magnetic\text{ }moment}{volume}=\frac{20\times {{10}^{-6}}}{{{10}^{-6}}}=20A/m\] \[\chi =\frac{I}{H}=\frac{20}{60\times {{10}^{3}}}=\frac{1}{3}\times {{10}^{-3}}=3.3\times {{10}^{-4}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner