A) \[70{}^\circ C\]
B) \[85{}^\circ C\]
C) \[60{}^\circ C\]
D) \[80{}^\circ C\]
Correct Answer: D
Solution :
Case I: Heat lost = Heat gained \[100\times {{s}_{A}}\times (100-90)=50\times {{s}_{B}}\times (90-75)\] \[2{{s}_{A}}\times 10={{s}_{B}}\times 15\]or\[4{{s}_{A}}=3{{s}_{B}}\] ?.(i) Case II: Heat lost = Heat gained \[100\times {{s}_{A}}\times (100-\theta )=50\times {{s}_{B}}\times (\theta -50)\] \[(100-\theta )=\frac{4}{3}\times \frac{1}{2}(\theta -50)\] \[\theta =\frac{400}{5}={{80}^{o}}C\]
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