A) two times the de-Broglie wavelength of the electron in the ground state
B) four times the de-Broglie wavelength of the electron in the ground state
C) half of the de-Broglie wavelength of the electron in the ground state
D) 1/4th of the de-Broglie wavelength of the electron in the ground state
Correct Answer: B
Solution :
\[\lambda =\frac{h}{mv}\]also \[\lambda =\frac{2\pi r}{n}\] \[\therefore \] \[r\propto {{n}^{2}}\] \[\therefore \] \[\lambda \propto n\] for n = 4, the de Broglie wavelength is four times that of ground state.
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