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JEE Main & Advanced JEE Main Paper (Held On 11 April 2015)

  • question_answer
    For plane electromagnetic waves propagating in the z direction, which one of the following combination gives the correct possible direction for \[\overset{\to }{\mathop{E}}\,\]and \[\overset{\to }{\mathop{B}}\,\]field respectively? [JEE Main Online Paper (Held On 11 April 2015)]  

    A) \[\left( \hat{i}+2\hat{j} \right)\]and\[\left( 2\hat{i}-\hat{j} \right)\]

    B) \[\left( -2\hat{i}-3\hat{j} \right)\]and\[\left( 3\hat{i}-2\hat{j} \right)\]

    C) \[\left( 2\hat{i}+3\hat{j} \right)\]and\[\left( \hat{i}+2\hat{j} \right)\]

    D) \[\left( 3\hat{i}+4\hat{j} \right)\]and\[\left( 4\hat{i}-3\hat{j} \right)\]

    Correct Answer: B

    Solution :

    In propagation of light \[\vec{E}\]and \[\vec{B}\]oscillate in mutually perpendicular directions. \[\vec{E}\times \vec{B}=\]direction of propagation = +z direction only option (d) satisfies both conditions of (a) \[\vec{E}\times \vec{B}=0\] (b) \[\left( \vec{E}\times \vec{B} \right)\]directed along the z-axis.


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