A) -130J
B) -12.0J
C) -140J
D) -110J
Correct Answer: D
Solution :
\[\therefore \] \[\int_{{}}^{{}}{dV}=-\int_{{}}^{{}}{{\vec{E}}}.d\vec{r}\] \[d\vec{r}=dx\hat{i}+dy\hat{j}\] \[\int_{{}}^{{}}{dV=-}\int_{{}}^{{}}{\left( 25\hat{i}+30\hat{j} \right).\left( dx\hat{i}+dy\hat{j} \right)}\] \[\int_{0}^{v}{dV=-}\int\limits_{0}^{2}{25dx}+\int\limits_{0}^{2}{30dy}\] \[V-0=-\left[ 25\left( x \right)_{0}^{2}+30\left( y \right)_{0}^{2} \right]\] \[V=-\left[ 25\times 2+30\times 2 \right]\] \[V=-110\]volt \[=-110J/C\]
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