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JEE Main & Advanced JEE Main Paper (Held On 11 April 2015)

  • question_answer
    Using equipartition of energy, the specific heat \[(in\text{ }J\text{ }k{{g}^{-1}}{{K}^{-}}^{1})\] of aluminium at room temperature can be estimated to be (atomic weight of aluminium = 27) [JEE Main Online Paper (Held On 11 April 2015)]  

    A)  25

    B)  410

    C)  925

    D)  1850

    Correct Answer: C

    Solution :

      For metals, there is no free motion but rather oscillation about mean position. Thus these have K.E. & P.E., which are almost equal. i.e. \[P.{{E}_{avg}}=K.{{E}_{avg}}=\frac{3}{2}RT\] \[\therefore \] \[T.E.=K.E.+P.E.\] \[\therefore \] \[T.E.=3RT\]per mole \[\therefore \] specific heat\[C=\frac{3R}{M}\] \[C=\frac{3\times 8.314}{27\times {{10}^{-3}}}\] \[\]


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