A) It is diamagnetic in nature
B) It is derivative of \[{{H}_{2}}{{O}_{2}}\]
C) \[N{{a}_{2}}{{O}_{2}}\]oxidises \[C{{r}^{3+}}\] to \[CrO_{4}^{2-}\]in acid medium.
D) It is the super oxide of sodium
Correct Answer: D
Solution :
\[N{{a}_{2}}{{O}_{2}}\]is peroxide of sodium not super oxide. The formula of sodium superoxide is \[Na{{O}_{2}}.\]
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